A ball is dropped from a cliff, what will be the velocity and acceleration after 2 second? Take g=9.8m/s2
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Answered by
2
v = u + gt
v = 0 + 9.8(2)
v = 19.6 m/s
acceleration is always 9.8 m/s^2 in this case
v = 0 + 9.8(2)
v = 19.6 m/s
acceleration is always 9.8 m/s^2 in this case
Answered by
2
U=0; a=9.8m/s2;t=2sec
V=u+at
V=9.8*2=19.6m/sec
V=u+at
V=9.8*2=19.6m/sec
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