Physics, asked by Asessment9368, 1 year ago

A ball is dropped from a height h when it reaches the ground its velocity is 40m/s

Answers

Answered by abdulbasith93
5
 {v}^{2} - {u}^{2} = 2as

 {40}^{2} - {0}^{2} = 2 \times 10 \times s

1600-0=20*s

s=80
Answered by danover244
0

Answer:

80m

Explanation:

v=sqrt2gh

solving we get h=80m

hope it helps

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