A ball is dropped from a height of 10m. If the energy of the ball is reduced to 40% after striking the ground,how much high can the ball bounce back ?? (g=10m/s²)
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Answered by
2
in this question we apply. MGH
h =10
g=10
m=40
MGH=10×10×40=4000
h =10
g=10
m=40
MGH=10×10×40=4000
rajid:
but mass is not given....
it is the energy reduction which is 40 %
i don know
okay
Answered by
6
Since, height = 10 m, Acceleration due to gravity(g) = 10 m/s^2
Let the mass be m
Therefore, Potential Energy= m x g x h
=> Potential energy = m x 10 x 10 =100m
SInce, Inital Potential energy is always equal to final kinetic energy...
Therefore, Original kinetic energy= 100m
After bouncing back, Reduced Kinetic energy = 40% of 100m = 40m
Since, Initial kinetic energy = Final potential Energy
Therefore, 40m = m x g x h ( Since, mass remains constant
=>40 = 10 x h and thus gets cancelled out)
=> h = 4 metre. Ans
Let the mass be m
Therefore, Potential Energy= m x g x h
=> Potential energy = m x 10 x 10 =100m
SInce, Inital Potential energy is always equal to final kinetic energy...
Therefore, Original kinetic energy= 100m
After bouncing back, Reduced Kinetic energy = 40% of 100m = 40m
Since, Initial kinetic energy = Final potential Energy
Therefore, 40m = m x g x h ( Since, mass remains constant
=>40 = 10 x h and thus gets cancelled out)
=> h = 4 metre. Ans
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