A ball is dropped from a height of 20 m. At the same instant another ball is
thrown up from the ground with a speed of 20 m/s. When and where will the
balls meet?
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Answer:
Choose a frame of reference in which the ball thrown upwards is stationary. In other words imagine what it wouldlook like if you were observing from a point on the upward travelling ball.
At the start you would be stationary, you would see the other ball initially moving towards you at 20m/s and it would accelerate at g.
Use the equations of uniformly accelerated motion (suvat) to find the time it takes for a collision. (s=ut + 1/2 at^2)
In this time the upward travelling ball will have covered a distance given by:
dist =speed x time =20 x t. This is how far from the floor the collision takes place.
Explanation:
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