Question

A ball is dropped from a height of 20m. If its velocity increases uniformly at the rate 10m/s2 with what velocity and after what time will it strike the ground?

Answer 1

Explanation:

Jun-2016 · If its velocity increases uniformly at the rate of 10m/s2 then with what velocity will it strike the ground

Answer 2

Explanation:

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 m

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1t = (v-u)/a

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1t = (v-u)/aˆ´Time taken by the ball to strike = (20-0)/10

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1t = (v-u)/aˆ´Time taken by the ball to strike = (20-0)/10= 20/10

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1t = (v-u)/aˆ´Time taken by the ball to strike = (20-0)/10= 20/10= 2 seconds