Physics, asked by akshatlapsha8, 3 days ago

A ball is dropped from a height which takes 4 sec to reach the ground. Find the height from where the ball is thrown​

Answers

Answered by kanishkajoshi2007
0

Answer:

u =0 m/s

g= 9.8m/s^2

t= 4s

h=s=?

s=ut +1/2 gt^2

s= 0×4 + 1/2 ×9.8 ×(4)^2

s= 0+78.4 m

s= 78.4 m

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