A ball is dropped from a height which takes 4 sec to reach the ground. Find the height from where the ball is thrown
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Answer:
u =0 m/s
g= 9.8m/s^2
t= 4s
h=s=?
s=ut +1/2 gt^2
s= 0×4 + 1/2 ×9.8 ×(4)^2
s= 0+78.4 m
s= 78.4 m
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