a ball is dropped from a high rise platform at t=0 starting from rest. after 6 sec another ball is thrown downwards from same platform with a speed v. the two ball meet at t=18s. what isthe value of v?
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Given in ball 1,
U=0
A=9.8m/s²
T=18s
Since T=u/g
:. putting value
18=u/9.8
18×9.8=u
176.4m/s=u(V)
(ÆÑẞWĒR)
indusinghkancha:
Is the answer correct?
no
75m/s
आपका सवाल क्या है? आप initial velocity जानना चाहते है। या final velocity?
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