Question

A ball is dropped from a high rise platform t = 0 starting from rest. afte4r 6 s another ball is thrown downwards from the same platform with a speed υ. the two balls meet at t = 18 s. what is the value of υ?

Answer 1

hope this helps you, sorry for the bad image quality

Answer 2

A = 10 m/s²

DISTANCE COVERED BY BALL A IS EQUAL TO THAT OF BALL B.

USING SECOND EQUATION OF UNIFORMLY ACCELERATED MOTION.

DISTANCE COVERED BY BALL A =
$s(a) = ut + \frac{1}{2} a {t}^{2} \\s(a) = \frac{1}{2} \times 10 \times {18}^{2} \\ s(a) = 5 \times 324 \\ s(a) = 1620 \: metres \: ....... \: (1)$
DISTANCE COVERED BY BALL B =

$s(b) = ut + \frac{1}{2} a {t}^{2} \\ s(b) = u(18 - 6) + \frac{1}{2} \times 10 \times {(18 - 6)}^{2} \\s(b) = 12u + 5 \times 144 \\ s(b) = 12u + 720 \: ....... \: (2)$
WE KNOW S(A) = S(B)

EQUALISING (1) AND (2)

12U + 720 = 1620

12U = 1620-720

12U = 900

U = 900/12

U = 75

BALL B HAVE BEEN THROWN DOWNWARDS WITH THE INITIAL VELOCITY OF 75 M/S.

PLZ MARK IT AS BRAINIEST ANSWER AND DROP A ♥