Question

a ball is dropped from a hight of 5 m. where will it suffer the maximum acceleration due to gravity

Answer 1

just touching before the ground cause

$a = \frac{g \times m_{e} }{ { r_{e} }^{2} }$
"a" stands for acceleration due to gravity
g stands for gravitational constant
me for mass of earth
and re for radius of earth

radius less just before ground