Question

A ball is dropped from a vertical tower of height 12m. After striking the ground it bounces back with a height of 9m. Calculate the total time in complete motion.
Plz plz plz plz plz answer correct tommorow is my physics paper

Answer 1

Answer:

Let mass of the ball be m.

Before Striking

Height of the ball = 12m

​G.P.E 1 = m*10*12

After Striking

Height of the ball = 9m

G.P.E 2 = m*10*9

Fraction

G.P.E 1/G.P.E 2 = m*10*12/m*10*9 = 3/4

Loss of K.E = 1- 3/4 = 1/4

So 1/4 of K.E is lost on striking the ground.

(Hope I answered the question)

Explanation:

Answer 2

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