Question

a ball is dropped from a window 50 m above the ground.
a. how long does it take the ball o reach the ground?
b. what is its final velocity?

Answer 1

i-

u=0 m/s
v=?
a=10m/s^2 (accelaration due to gravity)
s=50m
v^(2)=u^(2)+2as
v^(2)=0+2×10×50
v^(2)=1000
v=√(1000)
v=10√10m/s
v= 31.62m/s


ii-

v=u+at
31.62= 0+10×t
31.62=10t
t=31.62/10
t=3.162 sec.

Answer 2

a. 3.162 s.

b. 31.62 m/s.

Given:

Displacement, s = 50 m.

Initial velocity, u = 0 m/s.

Acceleration due to gravity, a = 10 m/s.

Tp Find:

a. Time taken by the ball to reach the ground, t.

b. Final velocity v.

Solution:

Firstly, to find the time taken by the ball to reach the ground, we need to know its final velocity, v. So we begin with finding the answer for subdivision b.

b. Formula : $v^{2} = u^{2} + 2as$

$v^{2} = 0 + 2(10)(50)$

$v^{2} = 1000$

$v = \sqrt{1000}$

$v = 10\sqrt[]{10}$

Final velocity, v = 31.62m/s

a. Formula: v = u + at

31.62= 0 + (10)(t)

10t = 31.62

t = 31.62/10

t = 3.162

Time taken by the ball to reach the ground, t = 3.162 s.