The product of 4 consecutive even numbers is always divisible by:
A.
600
B.
768
C.
864
D.
384
Answers
Answered by
9
answer is D , 384
let us take product of first 4 prime numbers
2*4*6*8 = 384
let us take any other 4 consecutive even numbers
16*18*20*22
it can be written as
2*4*6*8*330
so we can say 2,4,6,8 are the factors of the product of any four consecutive even numbers
note: even though 0 is even number, it is not taken into count
let us take product of first 4 prime numbers
2*4*6*8 = 384
let us take any other 4 consecutive even numbers
16*18*20*22
it can be written as
2*4*6*8*330
so we can say 2,4,6,8 are the factors of the product of any four consecutive even numbers
note: even though 0 is even number, it is not taken into count
Leukonov:
actually even if zero is taken into accout. The product would be zero. and Zero Divided by any no: being Zero itself→Zero is divisible by any No:
product of 4,6,8,10= 1920 how can we know which option is divisible by this i mean if we have different options
pls mark brainliest
Answered by
1
384 - It is always divisible by 4 (24 )4! = 16(24)=384
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