A ball is dropped from height h and another from 2h.the ratio of time taken by two balls
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s = ut + 1/2at1 2
s=h
h = 4.9 t1 2
t1 = √h/4.9
t2 = √2h/4.9
t1:t2 = 1:√2
s=h
h = 4.9 t1 2
t1 = √h/4.9
t2 = √2h/4.9
t1:t2 = 1:√2
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