Question

What is the empirical formula of a compound that contains 43.38% sodium, 11.33% carbon, and 45.29% oxygen?

Answer 1

the final answer is Na2co3...

Answer 2

Answer:

Na2CO3

Explanation:

43.38% of Na

11.33% of C

45.29% of O

Implies relative ratio if atoms

=(43.38/23):(11.33/12):(45.29/16)

=1.88:0.94:2.82

=2:1:3

So 2Na, 1C and 3O

Na2CO3