Physics, asked by ry2175665, 1 year ago

A ball is dropped from height of 45 m and rebounds with a velocity 3/5 th of the velocity with which it hits the ground. The time interval between first and
second bounces is [Take g = 10 m/s?]
(1) 8.2 s
(2) 54 s
(3) 24 s
(4) 3.6 s​

Answers

Answered by golurajsingh7th
0

Answer:

I taste your answer is 3

Explanation:

just i thinking no perfect answer

Answered by sjha051982
1

Answer:

8.2 s

Explanation:

If you use the formula v*v - u*u=2gh

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