A ball is dropped from height of 45 m and rebounds with a velocity 3/5 th of the velocity with which it hits the ground. The time interval between first and
second bounces is [Take g = 10 m/s?]
(1) 8.2 s
(2) 54 s
(3) 24 s
(4) 3.6 s
Answers
Answered by
0
Answer:
I taste your answer is 3
Explanation:
just i thinking no perfect answer
Answered by
1
Answer:
8.2 s
Explanation:
If you use the formula v*v - u*u=2gh
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