A ball is dropped from the roof of the building . It pass a window in one tenth of a second . Find the distance between the top of the window and the roof
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That is k = 1/2gt² ( From the second equation of motion)
So it travels k+2 m in t + 0.1seconds .
k + 2 = 1/2g(t+ 0.1)²
2 = 0.005 * 10 + 0.1(10)t
2= 0.05 + t
2 - 0.05 = t
1.95 = t.
Explanation:
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