Question

A ball is dropped from the top of a building. It takes 15 seconds to reach the ground. Find the height of the building. (Tale g = 10 m/s2.)​

Answer 1

Answer:

t=15 sec

g=10m/s

u=0

By 2nd equation of motion

h= ut+1/2at^2

h=0*15+1/2*10*15^2

h=0+1/2*10*225

h=5*225

h=1125m

Therefore,the height of the building is 1125m