Question

a ball is dropped from the top of a building of height 80m. At same instant another ball is thrown upwards with speed 50m/s from the bottom of the building. The time at which balls will meet is

Answer 1

BEST ANSWER;
When the two balls meet the time taken to travel say ‘ t sec ‘ and the height from the ground ‘h’ for both the balls are same. Hence the determining equation is :

h = 80 - ½*g*t² ——- for ball thrown from the top of the 80 m. building

h = 50t-(1/2)*g*t² ———— for the ball thrown up from the ground

h = 80 - ½*g*t² = 50t-(1/2)*g*t²

⇒ 50t = 80 or t = 80/50 = 1.6 sec.

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Answer 2

I hope you understand .