Question

A ball is dropped from the top of a tower 40 m height what is the best when it has covered 20 m what would be its velocity when it hits the ground take the 10 M per second square​

Answer 1

this is the answer I hope it would help you

Answer 2

1/2 mv^2 = mgh

V = root of 2gh

Here h = 40 - 20 = 20

V= √(2×10×20)

V= 20m/s

2. When it fall on ground

h=40m

V= √(2×10×40)

V=28.28m/s

Hope it helps, feel free to mark as brainlliest...