Question

Friends, please tell what is my mistake in this question!!

Answer 1

hope this helps you........

Answer 2

$\huge \bf\red{\mid{\overline{\underline {Answer}}} \mid}$

Let R be the resistance of the both the series and the parallel connection. Let V be the potential difference in both the cases. The Joule’s heating is given by :

$\boxed{H = I^2Rt}$

$\underline{\bold {For\:series \:combination;}}$

Resistance = R + R = 2R

By Ohm's law, $\boxed {V=IR}$

I = V/R = V/2R

Hence, heat produced, H = I^2Rt

=> H = V/2R × V/2R × 2R × t

=> H = V^2/2R

$\underline {\bold{For\:Parallel\:Combination;}}$

1/R' = 1/R + 1/R + 1/R = 2/R

R' = R/2

By Ohm's law, $\boxed {V=IR}$

I = V/R = V/R/2 = 2V/R

Hence, Heat produced, H = I^2Rt

=> H' = 2V/R × 2V/R × R/2 ×t

=> H' = 2V^t/R

Therefore, the ratio of the heat produced is:-

H/H' = V^2t/2R /2V^2t/R = V^2t/2R × R/2V^2t = 1/4

Hence, answer is :-

$\boxed{\Huge\bold {1:4}}$