A ball is dropped from the top of a tower 40 m high. What is its velocity when it has
covered 20 m ? What would be its velocity when it hits the ground?
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The velocity depends on height as v=(2gh)^1/2
when it is dropped from the height of 40m the velocity will be (approx.)=(800)^1/2
but at h=20; v= 20m/s. and when it hits the ground the v becomes zero.
when it is dropped from the height of 40m the velocity will be (approx.)=(800)^1/2
but at h=20; v= 20m/s. and when it hits the ground the v becomes zero.
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Answer:
The velocity depends on height as v=(2gh)^1/2
when it is dropped from the height of 40m the velocity will be (approx.)=(800)^1/2
but at h=20; v= 20m/s. and when it hits the ground the v becomes zero.
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