Question

A ball is dropped from the top of a tower 40m high. What is its velocity when it hits the ground?​

Answer 1

Answer:

Hey !! Here is your answer : u=0m s=20m a=g=10m/s^2 From the 3rd equation of motion: v^2-u^2=2gs v^2-0^2=2×10×20 v^2=400 v=root under 400 v= 20m/s u=0m s=40m g=10m/s^2 v^2-u^2=2gs v^2-0^2=2×10×40 v^2=800 v=root under 800 v= 28.28 m/s Hope it will help you

Answer 2

Answer:

Here is your answer : u=0m s=20m a=g=10m/s^2 From the 3rd equation of motion: v^2-u^2=2gs v^2-0^2=2×10×20 v^2=400 v=root under 400 v= 20m/s u=0m s=40m g=10m/s^2 v^2-u^2=2gs v^2-0^2=2×10×40 v^2=800 v=root under 800 v= 28.28 m/s Hope it will help you