A ball is dropped from the top of a tower of height 100m. Simultaneously , another ball was trown upwaqrd from thr bottom of the tower with a spee of 50m/s. These two balls would cross each after a time
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rthey will meet after 2second. assume that ball thrown down travelled distance x then ball b travelled distance 100-x then use S= ut-1/2gt² so -x= 0×t-10×t²/2= x=5t² 100-x= 50t-10×t²/2. 100-x= 50t-5t² from x= 5t² 100-5t² = 50t-5t² so. 100= 50t t= 2 sec.
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