Question

a ball is dropped from the top of a tower. the distance travelled by the ball in the last second is 40m. find height of tower.

Answer 1

as acceleration is constant then by formula. s=a/2(2n-1). where a=10 and s=40 so10/2(2n-1)=40. so n=4.5sec. now a=10. u=0.t=4.5 so. s=ut +1/2at^ s=5*4.5*4.5=101.25 m

Answer 2

Answer:101.25

Explanation:

use s=u+a(n-1/2)