Question

A ball is dropped into a well in which the water level is at a depth 'h' below the top. If the speed of sound is 'c'. Then the time after which the splash is heard will be ??
Plz help me with this..

Answer 1

Hey mate!

Here's your answer!!
Time taken for ball to reach water below.

Using h = 1/2gt² t = √(2h/g).......(1)

Time taken for sound to return back Speed of sound = c.

Therefore using distance/speed is time taken....

t2 = h/c.......(2)

Adding (1) and (2)
We get √(2h/g ) + h/c = T

Taking h common...... T=h(√(2/gh)+1/c)

$h( \sqrt \frac{2}{gh} + \frac{1}{v} )$

HOPE IT HELPS!
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