Question

From 1 to 100 numbers 3 numbers are selected at random. What is the probability that the numbers selected will have an odd sum?

Answer 1

Solution:-

given by:-

》 1 to 100 numbers

》slecteble are 3 numbers randam

》sum is odd ,

then ,

》if tree odd numbers

》Odd+Odd+Odd=Odd)

》two even and one odd

》(Even+Even+Odd=Odd);


now ,
》P(OOO)=(1/2)^3;

》P(EEO)=3×(1/2)^2×1/2=3/8

by 3 as the scenario of two even numbered and one odd numbered can occur in 3 different ways: EEO, EOE, or OEE);

》So P=1/8+3/8=1/2.

》answer is 1/2

☆ i hope its help☆

Answer 2

Step-by-step explanation:

Hope you understand. this was a hard question for me but not for you now