Question

A ball is dropped vertically from a height of h onto a hard surface. If the ball rebounds from the surface with a fraction r of the speed with which it strikes a the latter on each impact, what is the net distance travelled by the ball up to the 10th impact? (Guys, please answer this question asap, I'll mark the best answer as brainliest)​

Answer 1

Answer:

15 m

Explanation:

In case of rebound, we have the total distance traveled as :

d=h( 1−e 21+e 2 )d=9( 1−0.5 21+0.5 2 )d=9( 0.751.25 )md=9× 35

md=15m