A ball is falling freely from a tower of height 5m. how much momentum does it transfer to the Flor if it's mass in 500g. take a=10mper .sec
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Explanation:
ANSWER
Given,
Height of tower = 5m
Mass of body = 500g =0.5kg
Initial velocity, u = 0m/s
Acceleration, a = 10m/s^2s2
Now
to find the final velocity of body we will use the 3rd law of Kinematics =>
V^2 - u^2 = 2a×s
=> V^2 - 0 = 2(10)×(5)
=>V^2 = 100
=> V = 10m/s.
Hence the final velocity of body is
10m/s.
Now we know that =>
Momentum, p = mass × velocity
=>p = m × v
=>p = 0.5 × 10
=>p = 5kg m/s
Hence the momentum of body is
5kgm/s.
Now we know that =>
Kinetic energy = 1/2 × m × v^2
=>K. E = 1/2 × 0.5 × 100
=> K. E = 25 joules.
Hence the body will have an kinetic energy of 25J which will be transfered.
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