Question

a ball is falling freely from certain high it reaches ground after 3 second if 30 velocity of the boll while touching the ground. calculate the acceleration ?​

Answer 1

Answer:

using Newton's first equation of motion which is

v=u+at

v=30,u=0(as object was at rest),t=3,a=?

30=0+3a

a=10m/square

Answer 2

${\underline {\underline {\large {\bf { Correct \: Question: } }}}}$

A ball is falling freely from certain high it reaches ground after 3 second if velocity of the ball while touching the ground was 30m/s,Calculate the acceleration.

${\underline {\underline {\large {\bf { Required \: Solution: } }}}}$

Given:

• u (initial velocity) = 0m/s [ Whenever the body falls from a height, its initial velocity is taken as 0 ]

• v (final velocity) = 30m/s

• t (time taken) = 3sec

To calculate:

• Acceleration (a)

Calculation:

Using the acceleration formula:–

• ${\underline {\boxed {\large {\sf {\pink { a = \dfrac{v-u}{t} } }}}}}$

⠀⠀⠀$\bf { ⇢ a = \dfrac{30-0}{3} }$

⠀⠀⠀

⠀⠀⠀

⠀⠀⠀$\bf { ⇢ a = \dfrac{30}{3} }$

⠀⠀⠀

⠀⠀⠀

⠀⠀⠀$\boxed { \bf { ⇢ a = 10m/{s}^{2} }}$

Also,

By using the first equation of motion:

• ${\underline {\boxed {\large {\sf {\pink { v = u +at} }}}}}$

⠀⠀⠀$\bf { ⇢ 30 = 0 + a \times 3}$

⠀⠀⠀

⠀⠀⠀

⠀⠀⠀$\bf { ⇢ 30 = 0 + 3a }$

⠀⠀⠀

⠀⠀⠀

⠀⠀⠀$\bf { ⇢ 30 = 3a }$

⠀⠀⠀

⠀⠀⠀

⠀⠀⠀$\bf { ⇢ a = \dfrac{30}{3} }$

⠀⠀⠀

⠀⠀⠀

⠀⠀⠀$\boxed { \bf { ⇢ a = 10m/{s}^{2} }}$

[ You can apply any of these two formulae. ]

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${\underline {\underline {\large {\bf { ✭ Know \: More!!} }}}}$

• Acceleration is the rate of change in velocity over time.
• It is a vector quantity.
• Si unit = $\boxed { \bf {m/{s}^{2} }}$

Equations of motion:

• v = u + at

• s = ut + ½at²

• v² – u²= 2as

Laws of motion:

First law of motion:

✤ An object in motion will remain in motion unless acted upon by an outside force. An object at rest will remain at rest unless acted upon by an outside force.

Second law of motion:

✤ The acceleration of the body is directly proportional to the force acting on it and is inversely proportional to its mass and takes place in the same direction of the force.

Third law of motion:

✤For every action there is an equal opposite reaction.

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