A ball is gently dropped from a height of 20 m. If its velocity
increases uniformly at the rate of 10 ms?, with what velocity will it strike the ground?after what time will it strike the ground
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Answer:
20m/s
Explanation:
u = 0 m/s
a = 10m/s^2
s = 20m
v^2 = u^2 + 2as
v = sqrt( 0^2 +2*10*20)
v= sqrt(400)
v= 20m/s
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