A ball is gently dropped from a height of 20m if its velocity is zero increased uniformly @ 10 metre per second square with what velocity will it strike the ground also calculate the time at which it is strike
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Given , a=10m/s^2
h or S=20m
By using the formula ,
1)Acceleration=change in velocity/time
since, velocity=distance/time
So,a=distance/time^2
10=20/t^2 t^2= 2s^2.
t=1.4s
2) velocity with which ball strikes the ground=d/t
=20/1.4
=14.3 m/s.
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