Question

A ball is gently dropped from a height of 45m. If it's velocity increase uniformly at the rate of 10m/s with what velocity will it strike the ground? After what time will it strike the ground?

Answer 1

Answer:

Velocity=30m/s and Time=3sec

Explanation:

Displacement=45m

Acceleration=10m/sec^2

$v^{2}$ = $u^{2}$+2as

$v^{2}$=2*10*45

$v^{2}$=900

v=$\sqrt{900}$

v=30

And

a=v-u/t

10=30/t

t=30/10

t=3