Question

a ball is gently dropped from aheight of 20m. if its velocity increases uniformly at the raye of 10ms², with what velocity will it strike the ground? after what time will it strike the ground?

class 9 questions of physics​

Answer 1

Answer:

Velocity - 20 meter/second

Time taken - 2 second

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Answer 2

Answer:

20 m/s,  2 seconds

Explanation:

Distance s = 20 m

Initial velocity u = 0

Acceleration = 10 m/s²

Now, according to the equation of motion v² = u² + 2as

v² = 0 + 2*10*20

v² = 400

Thus, v = √400

v = 20 m/s

Now, According to the equation of motion, v = u + at

t = (v-u)/a

So, t = (20 - 0)/10

t = 2 seconds

Therefore,

Velocity = 20 m/s

Time = 2 seconds

Hope it helps!