Question

sin sqare 20 degree+sin square 70 degree / cos square 20 degree +cos square 70 degree + sin (90- theta) × sin theta / tan theta +cos(90-theta)×cos theta /cot theta​

Answer 1

Answer:

Step-by-step explanation:

(Sin²20°  + Sin²70°)/(SinθCos(90°-θ)  + CosθSin(90°-θ)) = 1

Step-by-step explanation:

(Sin²20°  + Sin²70°)/(SinθCos(90°-θ)  + CosθSin(90°-θ))

Using Sinθ = Cos(90°-θ)

& Cosθ = Sin(90° - θ)

Sin20° = Cos(90° - 20°) = Cos70°

= (Cos²70°  + Sin²70°)/(SinθSinθ   + CosθCosθ)

=(Cos²70°  + Sin²70°)/(Sin²θ   + Cos²θ)

using Sin²θ   + Cos²θ = 1

= 1 / 1

= 1

(Sin²20°  + Sin²70°)/(SinθCos(90°-θ)  + CosθSin(90°-θ)) = 1

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