A ball is kicked at an angle of 30 degree with the vertical if horizontal component of its velocity is 19.6 M per second find the Max Height and the horizontal range
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Since the angle of the ball in the question is with reference to vertical axis, for horizontal axis we have the angle as 60 degrees( x ).
Horizontal velocity is 19.6 m/s
ucosx = 19.6
u = 39. 2 m/s
Maximum height = ( usinx )2 / 2 * g
Maximum height = 58.8 m
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