Question

A ball is moving in a circular path with diameter 28m covers one revolution in 10 seconds calculate the speed with which it
is moving in the path?​

Answer 1

Answer:

8.8 m/s

Explanation:

v=2πr/t

v= $\frac{(2)(22/7)(14)}{10\\}$

v= 88/10

v=8.8 m/s

Answer 2

$\large{\red{ \bf{ \underline{ \underline{Answer }}}}} \\ \\ \sf\purple{ 8.8 \: m/s} \\ \\ \pink{ \underline{ {\sf{Given}}}} \\ \\ \sf{ \rightarrow \:Diameter = 28 \: cm } \\ \\ \sf{\rightarrow \: Time = 10 \: sec} \\ \\ \sf{ \blue {\underline{To \: Find}}} \\ \\ \sf{\rightarrow Speed=?}\\\\ \green\bigstar\sf\green {\underline{ Solution}}$

The Total Path covered is one Circle,

Therefore the total distance covered in one revolution is the circumference.

Circumference

$\sf{ = 2\pi r} \\ \\ \sf{ \implies 2\pi \times \frac{28}{2} } \\ \\ \sf{ \implies 2 \times \frac{22}{7} \times \frac{28}{2} } \\ \\ \sf{ \implies 88 \: m}$

Total time taken for 1 revolution is 10 sec

$\sf{ \therefore \: speed \large= \frac{distance}{time} } \\ \\ \sf{ \implies \frac{88}{10} } \\ \\ \sf{\purple{ \implies}}\sf{\purple{\underline{\boxed{\text{8.8 \: m/sec}}}}}$