Question

A ball is projected from point a with velocity 10 m/s perpendicular to the inclined plane inclined at an angle 30 degree. Range of the ball on the inclined is? ( Ans : 40/3 )

Answer 1

this is the answer for this question

Answer 2

Answer:

Let the striking angle be y=30 and the reverting angle will be x=(90-30)=60 from the inclined plane.

Thus by using the formula of range we can find the range of the ball on the inclined plane.

R= u^2(sin(2x+y) + siny)/g*cos^2y.

R=100(sin(2*60+30) + sin30))/ g*cos^2(30).

R=100(sin150 + 1/2)/10*(3/4).

R = 10 * (1/2 + 1/2)/3/4.

R=40/3 meter.