A ball is projected from the ground into the air. At a height of 15 m, its velocity is observed to be = 7i+10) in m/s. The maximum height the ball will
rise is (g = 10m/s2
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Answer:
Hi I will answer you
Explanation:
At height h=9.1m
v
=7.6
i
^
+6.1
j
^
v
y
=6.1m/s
Now, v
y
2
−u
y
2
=2ah
(6.1)
2
−u
y
2
=−2×10×9.1
u
y
2
=(6.1)
2
+182
=219.21m
2
/s
2
Maximum height, H=
2g
u
y
2
=
2×10
219.21
=10.96m
H=11m
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