Question

a ball is projected obliquely with a velocity 49m\s strikes the the ground at a distance of 245m from a point of projection it remaind in air for

Answer 1

2016-09-01T04:14:47+05:30

Let the angle of projection be A.
Range R = 245 m u = 49 m/s g = 9.8 m/s

R = u^2 sin2A / g
so sin2A = R * g/u^2 = 1 => A =45 deg.

Time of flight = R/(u cosA) = 245 *√2 /49 = 5√2 = 7.07 seconds.

Answer 2

Answer:

Let the angle of projection be A.

Range R = 245 m u = 49 m/s g = 9.8 m/s

R = u^2 sin2A / g

so sin2A = R * g/u^2 = 1 => A =45 deg.

Time of flight = R/(u cosA) = 245 *√2 /49 = 5√2 = 7.07 seconds.