a ball is projected obliquely with a velocity 49m\s strikes the the ground at a distance of 245m from a point of projection it remaind in air for
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2016-09-01T04:14:47+05:30
Let the angle of projection be A.
Range R = 245 m u = 49 m/s g = 9.8 m/s
R = u^2 sin2A / g
so sin2A = R * g/u^2 = 1 => A =45 deg.
Time of flight = R/(u cosA) = 245 *√2 /49 = 5√2 = 7.07 seconds.
Let the angle of projection be A.
Range R = 245 m u = 49 m/s g = 9.8 m/s
R = u^2 sin2A / g
so sin2A = R * g/u^2 = 1 => A =45 deg.
Time of flight = R/(u cosA) = 245 *√2 /49 = 5√2 = 7.07 seconds.
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Answer:
Let the angle of projection be A.
Range R = 245 m u = 49 m/s g = 9.8 m/s
R = u^2 sin2A / g
so sin2A = R * g/u^2 = 1 => A =45 deg.
Time of flight = R/(u cosA) = 245 *√2 /49 = 5√2 = 7.07 seconds.
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