Question

a ball is projected upwards from the foot of tower the ball crosses the top of the tower twice after an interval of 6s and the ball reaches the ground after 12s the height of the tower is (g=10ms)

Answer 1

what is the question?

Answer 2

In a projectile the time taken to reach the highest point from the point of projection is equal to the time taken to fall from the highest point to the point of projection. That means the time of ascent = time of descent

If the total time taken is 12sec then time taken to reach the highest point is 6sec.

Similarly in 6sec it crosses the same point, let's say point A(top of tower), so it takes 3 sec to reach the highest point and 3more secs to come back to point A.
Then see the attachment for the calculation.


HOPE IT HELPS.... :-)