Question

A ball is projected upwards with a velocity of 15 m/s at an angle of 25° with the horizontal. What is the horizontal range of the ball?

Answer 1

Answer:

ucos25°×2usin25°/g

g=acceleration due to gravity

Answer 2

Answer:

The correct answer is equal to 17.58m.

Explanation:

The ball is projected with a velocity of 15m/s.

The ball is projected at an angle of 25°.

R denoted as a horizontal range of the ball.

u denoted as the velocity of the ball.

g = acceleration due to gravity.

By the equation,

R=$u^{2}$sin2Ф/g

R=$15^{2}$sin2×25°/9.8

 = 17.58m

So, The horizontal range of the ball is equal to 17.58m.