Question

a ball is projected vertically up from a tower of 50m.it rises 20m above the tower and reaches the ground.find the diatance travelled and the magnitude of displacement in the vertical direction ​

Answer 1

Answer:

the distance covered is 90m and displacement is -50m

Answer 2

Answer:

The distance travelled by the ball is 90m and the magnitude of displacement in the vertical direction ​is 50m.

Explanation:

Given height of the tower, $H = 50m$

The maximum height reached by the ball from the top of the tower, $h = 20m$

The total distance travelled by the ball is equal to the sum of distance from A to B and from B to G as shown in the fig.

The height from B to G is the sum of height of the tower and maximum height reached by the ball.

Therefore, total distance travelled by the ball =$20+20+50=90m$

For the displacement, the initial position of ball was on the tower and final position is on the ground.

Therefore, the magnitude of displacement in the vertical direction ​is height of the tower = 50m