Question

A ball is projected vertically up from the ground with a velocity of 50ms-1 At the same time a stone is dropped from a tower of height
125 m. Take g = 10ms-2

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Answer 1

Explanation:

Initial velocity, u=50ms

−1

At maximum height final velocity, v=0

Apply first kinematic equation of motion

v=u+at

0=50−10t

t=5sec

Apply second kinematic equation of motion

v

2

−u

2

=2as

0

2

−50

2

=2(−10)h

h=125m

Hence, at maximum height final velocity is zero, time taken 5secand maximum height is 125m