Question

please help me please yaar please ​

Answer 1

Step-by-step explanation:

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Answer 2

In  △ A P B  and  △ A Q B

A P = A Q  (Given)

B P = B Q  (Given)

A B = A B  (Common Side)

∴ △ A P B ≅ △ A Q B ( S . S . S . )

⇒∠ P A B = ∠ Q A B ( C . P . C . T . C . )

⇒∠ P B A = ∠ Q B A ( C . P . C . T . C . )

Thus, AB is bisector of  ∠ P A Q  and  ∠ P B Q