Question

A ball is projected vertically up with a speed of 50 m/s . find the maximum height and the time to reach the maximum height and the speed at the maximum height ?

Answer 1

at maximum height velocity of ball = 0
use kinematic equation ,
v = u + at
0 = 50 - 10t
t = 5 sec
hence time reach to maximum height =5s

again ,
use v^2 = u^2 + 2aS
0 = (50)^2 -2 x 10 x S
S = 2500/20 = 125 m

hence ,
maximum height = 125 m

speed at maximum height = 0

Answer 2

v = u + at
0 = 50 - 10t
t = 5 sec
hence time reach to maximum height =5s.
v^2 = u^2 + 2aS
0 = (50)^2 -2 x 10 x S
S = 2500/20 = 125 m