Question

A ball is projected vertically up with a speed of 50 m/s. Find the maximum height the time to reach the maximum height, and the speed at themaximum heign( g=10 m/s²) (AS,) (Ans: 125m; 5s; zero)​

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

$\huge\underline{\mathcal Given}</p><p>$

u = 50 m/s

v = 0

We assume g = -10m/s2

(a)Maximum Height Reached is :-

We have ,

$\huge{\boxed{\mathcal {v}^{2}={u}^{2}+2gs}}$

$\large{\mathcal s={\frac{{v}^{2}-{u}^{2}}{2a}}}$

$\large{\mathcal s={\frac{{-50}^{2}}{2×-10}}}$

$\large{\mathcal s={\frac{-2500}{-20}}}$

$\huge{\boxed{\mathcal s=125m}}$

(b) The time to reach maximum height is Calculated as follows :-

We have,

$\huge{\boxed{\mathcal v=u+gt}}$

Thus ,

$\large{\mathcal t={\frac{v-u}{a}}}$

$\large{\mathcal t={\frac{0-50}{-10}}}$

$\huge{\boxed{\mathcal t= 5 s}}$

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