Question

A ball is projected vertically upwards with a velocity of 50m/s

Find time taken to reach max height
G=10m/s

Answer 1

Answer: 5 seconds.

Explanation:

MAX HEIGHT REACHED WHEN PROJECTED WITH 50m/s IS

==>h(max)=v²/2g=50×50/20=125m

==>max height reached is 125m

TIME TAKEN TO REACH MAX HEIGHT IS

t=√2h/g=√2×125/10=√25 seconds=5seconds.

HOPE IT WILL HELP YOU.........................

THANK YOU.

Answer 2

Answer:

Explanation:

Initial velocity (u) = 50 m/s

Final velocity  =  0(when the ball is at maximum height)

Acceleration due to gravity = - 10 m/s² (in this case deceleration is happening since speed is decreasing)

Using first equation of motion:

v = u + at

0 = 50 - 10t ⇒ 10t = 50

                          t = 5 seconds