Question

In a tight triangle ABC, right-angled at B, if tan A=1, then find value of 2sinA.cosA.

Answer 1

Step-by-step explanation:

if tanA = 1

then sinA/cosA=1/1

• the is equilateral right angled .
• then, 2 (1*1)=2
• therefore 2sinA*cosA=2

Answer 2

Answer:given angleB=90°.

Also tanA=1.

Now, tanA=(BC/AB)=SinA/CosA=1

Or, SinA=CosA

Now, CosA=BC/AC

But AC=BC√2

Therefore, CosA=√2=SinA

Hence,2SinACosA= 2*√2*√2=4

Step-by-step explanation: