Question

a ball is projected vertically upwards with speed at half of maximum height is 20 m per second the maximum height updated by it is​

Answer 1

${\huge {\mathfrak {Answer :-}}}$

➡️ Let the ball attends 'h' height.

So, v^2 = u^2 - 2g(h/2)

Or, 0 = 400 - 2 * 10 (h/2)

Or, h/2 = 400/20 = 20.

Or, h = 40.

➡️ Hence, the height is 40 m. (approx).

That's it..