Question

a ball is projected with initial velocity of 18m/s at an angle of 30degrees.What is the time of flight of the ball​

Answer 1

Answer:

 1.84s

Step-by-step explanation:

to aproach this type of question

for vertical motion:

U= 18sin30

  =9m/s

considering the max height at which is projected

we use the equation below

V= U + at

V=0 at max height

and t is the time taken to reach max-height

thus 0=U+at

for upward motion acceleration is negative

implying that 0= 9 - 9.8t

simplfying t = 0.92s

This is not yet the answer.

The time taken for the flight is 0.92* 2=1.84s

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